6x^2-14x-96=0

Solution for 6x^2-14x-96=0 equation:

6x^2-14x-96=0

a = 6; b = -14; c = -96;
Δ = b2-4ac
Δ = -142-4·6·(-96)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-50}{2*6}=\frac{-36}{12}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+50}{2*6}=\frac{64}{12}
=5+1/3
$